Question 149785
I don't think you can solve this one without using algebra. Anways, here's the solution.

60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.

let x = width of rectangle A
let y = width of rectangle B

then Area of rectangle A = 25x
and Area of rectangle B = 25y

{{{0.6(25x) = 0.8(25y)}}}
{{{150x = 200y}}}
{{{x = 4y/3}}}
{{{25x = 25y + 25}}}
{{{x = y+1}}}
{{{y+1=4y/3}}}
{{{3y+3=4y}}}
{{{y=3}}}
{{{x=4}}}

PERIMETERa = {{{2(x+25)}}}
= {{{58}}}
PERIMETERb = {{{2(y+25)}}}
= {{{56}}}

PERIMETERa - PERIMETERb = 2cm