Question 149751
Assume you mean:
{{{3/(2y)}}} - {{{3/((2y+4))}}}
:
Common denominator would be 2y(2y+ 4)
Over a single denominator, combine like terms ;
{{{(3(2y+4) - 3(2y))/(2y(2y+4))}}} = {{{((6y + 12 - 6y))/(2y(2y+4))}}} = {{{12/(2y(2y+4))}}} = {{{12/((4y^2+8y))}}}
Factor out 4
{{{12/(4(y^2+2y))}}}
Cancel into the 12
{{{3/((y^2+2y))}}} or {{{3/(y(y+2))}}}