Question 149760
The volume of a bowling ball with 8" diameter:
{{{V = (4/3)(pi)r^3}}} r = half the diameter. = 8/2 = 4"
{{{V = (4/3)(3.14)(4^3)}}}
{{{V = (12.56/3)(64)}}}
{{{V = 267.9466}}} Round to nearest cubic inch...
{{{V = 268}}}cubic inches.