Question 149757
Let x=length of first side. 



Since "one side is twice as long as the first", this means that {{{y=2x}}}



Also, because "another is half as long as the first side", this means that {{{z=(1/2)x}}}




However, there's a problem. In order for any triangle to be constructed, the lengths of any two sides <font size=4><b>must</b></font> be greater than the length of the third side. So for instance, this means that {{{x+z>y}}}. 


{{{x+(1/2)x>2x}}} Plug in {{{y=2x}}} and {{{z=(1/2)x}}}



{{{(3/2)x>2x}}} Add



Since this inequality is <font size=4><b>never</b></font> true for any positive x values, this means that you cannot construct a triangle with sides of x, 2x, and {{{(1/2)x}}} (go ahead and try it out on paper if you don't believe me).



So I would double check the problem.