<PRE><B>Question 149706</B>
Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?

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Value EQUATION: 5N + 10D = 565
Value  EQUAT: 5(N+8) + 10(2D) = 1045
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Rearrange:
5N + 10D = 565
5N + 20D = 1045 - 80
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Subtract 1st from 2nd to get:
10D = 400
D = 40 (# of dimes)
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Substitute to solve for N:
5N + 400 = 565
5N = 165
N = 33 (# of nickels)
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Cheers,
Stan H.
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