Question 149659
A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position?
.
The diagonal of the 2x3 is:
x^2 = 2^2 + 3^2
x^2 = 4 + 9
x^2 = 13
x = sqrt(13)
.
The diagonal of the 1.5xsqrt(13) is:
x^2 = 1.5^2 + sqrt(13)^2
x^2 = 2.25 + 13
x^2 = 15.25
x = 3.91 inches