Question 149609
log(base2) x+log(base4) x + log(base8) x = 1

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[logx/log2] + [logx/2log2] + [logx/3log2] = 1

Multiply thru by 6log2 to get:

6logx + 3logx + 2logx = 6log2
11logx = 6log2
[logx/log2] = 6/11
log(base2) x = 6/11
x = 2^(6/11)
x = 1.45948...
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Cheers,
Stan H.