Question 149528
It's the second to last step. The error that occurs is a division by zero. 


If x=2, then x-2 is really 2-2=0


So {{{x-2=0}}}



So {{{x(x-2)=x-2}}} is really {{{x(0)=0}}}. 


In this step, there is a division by {{{x-2}}} to get {{{x(x-2)/(x-2)=(x-2)/(x-2)}}}



However, since {{{x-2=0}}}, this means that this happens {{{x(0)/(0)=(0)/(0)}}}


But you <font size=4><b>cannot</b></font> divide by zero. So this is where the flaw occurs. This is a common fallacy in the "proofs" of odd statements like 1=2 or 0=1. Or in this case, you're "proving" that x=1=2.