Question 149484
time=distance/speed

t=8/s


t-1/3=8/s+2


Plug in t


8/s-1/3=8/s+2


Common denominator on the left side=3s
24/3s-s/3s=8/s+2


Subtract the numerators
24-s/3s=8/s+2


Cross multiply
24s=-s^2+26s+48


Subtract the 24s from both sides
0=-s^2+2s+48


Factor
0=(-s+8)(s+6)


Then you solve for s
s=-6 or 8


Speed can't be negative, so make them positive
s=6 or 8


Plug in 6.
t=8/6


t=4/3


4/3-1/3=8/6+2
It is true!


there fore the original speed was 6 mph.