Question 149428
Name three consecutive positive even integers, A, B, and C.
{{{A=2N}}} 2N makes the integer even
{{{B=2N+2}}} Next even integer after 2N
{{{C=2N+4}}} Next even integer after 2N+2
{{{N>0}}} This makes the integers positive
{{{A*C=60}}} The product of first and third integer.
{{{2N(2N+4)=60}}}
{{{4N^2+8N-60=0}}}
{{{N^2+2N-15=0}}}
{{{(N+5)(N-3)=0}}}
N+5=0
N=-5, not allowed since N>0, from above.
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.
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N-3=0
N=3
{{{A=2N=6}}} 
{{{B=2N+2=8}}} 
{{{C=2N+4=10}}} 
The three integers are then 6, 8, and 10.