Question 149413
Write log ({{{x^2}}} -9)- log({{{x^2}}} +7x +12) as a single logarithm
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= log[(x^2-9)/(x^2+7x+12)]

= log[(x+3)(x-3)/(x+3)(x+4)]

= log[(x-3)/(x+4)]
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Cheers,
Stan H.