Question 149398
(a) 6^x-3 = 2^x 
Take the log of both sides to get:
(x-3)log6 = xlog2
x(log6-log2) = 3log6
x(log3) = 3log6
x = 3log6/log3
x = 4.8927...
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(b) log(5x-6) = 2log x
log(5x-6) = logx^2
x^2 = 5x-6
x^2-5x+6=0
(x-3)(x-2) = 0
x = 2 or x = 3

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Cheers,
Stan H.