Question 2506
1/(x-1) + 2/x = x/(x-1)
=> (x + 2(x-1))/x(x-1) = x/(x-1)
=> (3x-2)/x(x-1) = x/(x-1)
=> (3x-2)(x-1)/x(x-1) = x
=> (3x-2)/x = x
=> 3x-2 = x^2
=> x^2-3x+2 = 0
=> x^2-2x-x+2 = 0
=> x(x-2)-(x-2)=0
=> (x-1)(x-2)=0

According to the zero product rule
x=1,2