Question 149381
l=3w+6------------------The length of a rectange is 6in more than 3 times its width

w=w---------------------The width

w(3w+6)=(w+4)(3w-4)-----------------If the width were increased by 4 and the length decreased by 10, the area of the new rectangle would equal the area of the orignal rectangle


Distribute
3w^2+6w=3w^2+8w-16


Subtract 3w^2 from both sides
6w=8w-16

Subtrat 8w from both sides
-2w=-16


Divide by -2
w=8


l=3w+6
w=w


Length=30
Widht=8