Question 149379
for a circle of the form x^2+ax+y^2+by+c=d; the coordinates of the center are [(-a/2),(-b/2)]


circle P is centered at (3,-2) and circle Q is centered at (4,-5)


if by difference, you mean distance; then d=sqrt[(4-3)^2+(-5-(-2))^2] __ d=sqrt(10)