Question 149380
First graph the points (-2,5) and (3,0) 

{{{ drawing(500, 500, -7, 7, -7, 7,
 grid(1),
 graph( 500, 500, -7, 7, -7, 7,0),
 circle(-2,5,0.05),
 circle(-2,5,0.08),
 circle(-2,5,0.10),
 circle(3,0,0.05),
 circle(3,0,0.08),
 circle(3,0,0.10)

)}}}


Now draw a line through those points



{{{ drawing(500, 500, -7, 7, -7, 7,
 grid(1),
 graph( 500, 500, -7, 7, -7, 7,-x+3),
 circle(-2,5,0.05),
 circle(-2,5,0.08),
 circle(-2,5,0.10),
 circle(3,0,0.05),
 circle(3,0,0.08),
 circle(3,0,0.10)

)}}}


Now start at the point (-2,5) and move 5 units down (to get to the same level as the second point). Since we went 5 units down, this means that the rise is -5.

{{{ drawing(500, 500, -7, 7, -7, 7,
 grid(1),
 graph( 500, 500, -7, 7, -7, 7,-x+3),
 circle(-2,5,0.05),
 circle(-2,5,0.08),
 circle(-2,5,0.10),
 circle(3,0,0.05),
 circle(3,0,0.08),
 circle(3,0,0.10),

green(arc(-2,0.5,1,1,90,270)),
green(arc(-2,1.5,1,1,90,270)),
green(arc(-2,2.5,1,1,90,270)),
green(arc(-2,3.5,1,1,90,270)),
green(arc(-2,4.5,1,1,90,270))

)}}}



Now move 5 units to the right to get to the next point. Since we went 5 units to the right, this means that the run is 5.

{{{ drawing(500, 500, -7, 7, -7, 7,
 grid(1),
 graph( 500, 500, -7, 7, -7, 7,-x+3),
 circle(-2,5,0.05),
 circle(-2,5,0.08),
 circle(-2,5,0.10),
 circle(3,0,0.05),
 circle(3,0,0.08),
 circle(3,0,0.10),

green(arc(-2,0.5,1,1,90,270)),
green(arc(-2,1.5,1,1,90,270)),
green(arc(-2,2.5,1,1,90,270)),
green(arc(-2,3.5,1,1,90,270)),
green(arc(-2,4.5,1,1,90,270)),

blue(arc(-0.5,0,1,2,0,180)),
blue(arc(-1.5,0,1,2,0,180)),
blue(arc(0.5,0,1,2,0,180)),
blue(arc(1.5,0,1,2,0,180)),
blue(arc(2.5,0,1,2,0,180))
)}}}



So the rise is -5 and the run is 5. This makes the slope {{{m=rise/run=(-5)/(5)=-1/1=-1}}}


So the slope between the two points (-2,5) and (3,0) is {{{m=-1}}}