Question 149320
3/2x-6 + 1/x^2-9
Factor where you can:

3/[2(x-3)] + 1/[(x-3)(x+3)]

LCD: 2(x+3)(x-3)

=  [3(x+3) + 2]/LCD

= [3x+11]/[2(x^2-9)]

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Cheers,
Stan H.