Question 149304
Given : {{{5t^2-16t = -12}}}
{{{5t^2 -16t + 12 = 0}}}
the factor of 5 are 1 and 5. The factors of 12 are 1,12  and 2,6 and 3,4. We need to find the combination that provides a sum or -16.

16 = (2*5 + 1*6)

{{{5t^2 - 16t +12 = 0}}}
{{{(5t - 6)(t - 2) = 0}}}
Using the rule of zero, either one of the other term can be zero and the product is zero. So
Either {{5t - 6 = 0}}} or {{{t - 2 = 0}}}
Thus
t = 6/5  or t = 2


See this URL --> http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=algebra&s2=factor&s3=basic

Note that you must use x as the variable (just use x instead of t)