Question 149268
If x=1 is a solution and x=-8 is a solution, then 
the quadratic equation looks like.
{{{f(x)=(x-1)(x+8)}}}
because 
{{{x-1=0}}} for x=1
and 
{{{x+8=0}}} for x=-8
{{{f(x)=(x-1)(x+8)}}}
{{{f(x)=x*x+x*8+(-1)*x+(-1)(8)}}}
{{{f(x)=x^2+8x-x-8}}}
{{{f(x)=x^2+7x-8}}}