Question 149092
Let {{{P(x)}}} = population in year {{{2000 + x}}}
{{{P(10) = 5.89*e^(.0175*10)}}}
{{{P(10) = 5.89*e^.175}}} (use calculator {{{e^x}}} function)
{{{P(10) = 5.89*1.191}}}
{{{P(10) = 7.016}}}
The population will be 7,016,000 in year 2010