Question 148764
A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally. 
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Let w = width of parking lot
then
w+50 = length of parking lot
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Using Pythagorean theorem:
w^2 + (w+50)^2 = 250^2
w^2 + (w^2 + 100w + 2500) = 62500
2w^2 + 100w + 2500 = 62500
2w^2 + 100w - 60000 = 0
w^2 + 50w - 30000 = 0
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If it is too difficult factor, use the "quadratic equation".
You'll get two solutions:
150, -200
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since it can't negative:
width=150 ft
length = 200 ft
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*[invoke quadratic "x", 1, 50, -30000 ]