Question 148631
Trigo Identities.
We should know that 1+(tan^2x)=sec^2x also 1+(cot^2x)=csc^2x
Substituting these identities to the eqn (tan^2x)-(cot^2x)=(sec^2x)-(csc^2x)
{{{(sec^2x)-1-(csc^2-1)=(sec^2x)-(csc^2x)}}}
{{{sec^2x-cross(1)-csc^2x+cross(1)=sec^2x-csc^2x}}}
{{{sec^2x-csc^2x=sec^2x-csc^2x}}} ----------> Identical
<font><font size=4><b> Thank you,
Jojo</font>