Question 148706
Given : 
 
    A = x^2 + 5x +6

    h = x + 3

Required : 

    Length of the base b


                 Solution : 

    Area of a triangle A = {{{(bh/2)}}}

    Length of the base b = {{{2*A/h)}}}

                        b = {{{2(x^2 + 5x + 6)/(x + 3)}}}  

                        b = {{{(2x^2 + 10x + 12)/(x + 3)}}}    

                        b = 2x + 4  which is easily solved by division