Question 148658
two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord.
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If you draw them, you'll see that there is a triangle formed by the 2 centers and one of the points of intersection of the circle.  The chord is perpendicular to the line connecting the 2 circles, so it makes a right triangle with the radius and 1/2 of the line between the centers.
The radius is the hypotenuse = 10.
1/2 of the line connecting the centers = 6.
So 1/2 the chord = {{{sqrt(10^2 - 6^2)}}}
C/2= {{{sqrt(64)}}}
C/2 = 8
The chord = 16.