Question 142123
Factor completely by grouping:

{{{2y + mx^3 + my + 2x^3}}}

<pre><font size = 4 face = "verdana" color ="indigo"><b> 
Since we cannot factor the first two terms or the last
two terms, we try reversing the two middle terms:

{{{2y + my + mx^3 + 2x^3}}}

Now we can factor the first two terms AND the last two terms:

We factor {{{2}}} out of the first two terms and factor {{{x^3}}} 
out of the last two terms:

{{{y(2 + m) + x^3(m + 2)}}}

Notice that {{{(2+m)}}} is the same thing as {{{(m+2)}}}

So we replace the {{{(2+m)}}} by {{{(m+2)}}}

{{{y(m + 2) + x^3(m + 2)}}}

Now we have a common factor of {{{(m+2)}}}

So we factor {{{(m+2)}}} out

{{{(m+2)(y+x^3)}}}

Edwin</pre>