Question 148533
{{{(m/(m-n)(m+n))/((n+1)/(m+n)^2)}}}


{{{(m+n)^2=(m+n)(m+n)}}}

So plug that in:
{{{(m/(m-n)(m+n))/((n+1)/(m+n)(m+n))}}}


Flip the second fraction:

{{{(m/(m-n)(m+n))((m+n)(m+n)/(n+1))}}}


Cross out like terms:

{{{(m/(m-n))((m+n)/(n+1))}}}


Now multiply across

{{{(m(m+n)/(m-n)(n+1))}}}