Question 148493
{{{(y^2+7y+10)/(2y-4)}}} divided by {{{(y^2-3y-10)/(y-2)}}}


Factor everything possible


{{{(y+5)(y+2)/(2(y-2))}}} divided by {{{(y-5)(y+2)/(y-2)}}}


Cancel everything in common


{{{(y+5)/(2)}}} divided by {{{(y-5)/1}}}


Now flip the second one


{{{(y+5)/(2)}}} multiplied by {{{1/(y-5)}}}


Then multiply


{{{1(y+5)/(2)(y-5)}}}


Simplify the mess


{{{(y+5)/(2y-10)}}}


Take negative two out of the denominator


{{{(y+5)/-2(y+5)}}}


Cancel out like terms


{{{1/-2}}}