Question 148343
Give three ordered pairs that are solutions to the equation {{{3x - y = 8}}}. 

{{{3x - y = 8}}}
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Solve for y.
Add -3x to both sides to get rid of the 3x on the left
{{{3x-y-3x=8-3x}}}

{{{cross(3x)-y-cross(3x)=8-3x}}}
{{{-y=8-3x}}}

Multiply both sides by {{{-1}}}

{{{(-1)(-y)=(-1)8-(-1)3x}}}

{{{y=-8+3x}}}

{{{y=3x-8}}}

Make up any value for {{{x}}}, say {{{x=1}}} and substitute:

{{{y=3(1)-8}}} 
{{{y=3-8}}}
{{{y=-5}}}

So one ordered pair (x,y) is (1,-5)

Make up another value for {{{x}}}, say {{{x=3}}} and substitute:

{{{y=3(3)-8}}} 
{{{y=9-8}}}
{{{y=1}}}

So a second ordered pair (x,y) is (3,1)

Make up one more value for {{{x}}}, say {{{x=4}}} and substitute:

{{{y=3(4)-8}}} 
{{{y=12-8}}}
{{{y=4}}}

So a third ordered pair (x,y) is (4,4).

Edwin</pre>