Question 148320
(5/6)log(x) + 12log(y) - 6logx - logy

Rearrange and factor to get:
[(5/6)-6]logx + 11logy

[-31/6]logx + 11logy

= log[x^(-31/6)*y^11]

= log[y^11/x^(31/6)]
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Cheers,
Stan H.