Question 22389
Take the log of both sides of the equation to get the "x" out of the exponent.

log y = (1/(p-1))log x

Then divide both sides by log x to get:
   (logy)/(logx) = 1/(p-1)
Invert both sides to get:
p-1 = (logx)/(logy)

p = (logx)/(logy)-1
Substitute to get:
p= (log0.745)/(log2.65) -1
p=-1.30

Cheers,
Stan H.