Question 22394
<pre>  14x - 7      x<sup>2</sup> + 6x + 8      x<sup>2</sup> + 2x
----------- · ------------- ÷ -----------
x<sup>2</sup> + 3x - 4   2x<sup>2</sup> + 5x - 3    x<sup>2</sup> + 2x - 3

Invert the divided fraction and change the division to
multiplication:

  14x - 7      x<sup>2</sup> + 6x + 8    x<sup>2</sup> + 2x - 3
----------- · ------------- · -----------
x<sup>2</sup> + 3x - 4   2x<sup>2</sup> + 5x - 3      x<sup>2</sup> + 2x

Factor all numerators and denominators:

   7(2x - 1)    (x + 4)(x + 2)    (x + 3)(x - 1)
------------- · --------------- · --------------
(x + 4)(x - 1)  (x + 3)(2x - 1)      x(x + 2)

Write the product of the numerators over the product of 
the denominators:

7(2x - 1)(x + 4)(x + 2)(x + 3)(x - 1)
-------------------------------------
(x + 4)(x - 1)(x + 3)(2x - 1)x(x + 2)

Cancel the (2x - 1)'s

7<s>(2x - 1)</s>(x + 4)(x + 2)(x + 3)(x - 1)
-------------------------------------
(x + 4)(x - 1)(x + 3)<s>(2x - 1)</s>x(x + 2)

7(x + 4)(x + 2)(x + 3)(x - 1)
-----------------------------
(x + 4)(x - 1)(x + 3)x(x + 2)

Cancel the (x + 4)'s

7<s>(x + 4)</s>(x + 2)(x + 3)(x - 1)
-----------------------------
<s>(x + 4)</s>(x - 1)(x + 3)x(x + 2)

7(x + 2)(x + 3)(x - 1)
----------------------
(x - 1)(x + 3)x(x + 2)

Cancel the (x + 2)'s

7<s>(x + 2)</s>(x + 3)(x - 1)
----------------------
(x - 1)(x + 3)x<s>(x + 2)</s>

7(x + 3)(x - 1)
---------------
(x - 1)(x + 3)x

Cancel the (x - 1)'s

7(x + 3)<s>(x - 1)</s>
---------------
<s>(x - 1)</s>(x + 3)x
 
7(x + 3)
--------
(x + 3)x

Cancel the (x + 3)'s

7<s>(x + 3)</s>
--------
<s>(x + 3)</s>x

 7
---
 x

Edwin
AnlytcPhil@aol.com</pre>