Question 148266
1. if log 90=x, then x=
3 
2. if [x+2]=5, solve for x 
3. given the following linear equations: 
2x+3y=10
4x-6y=-28
solve for (x,y) if there is a solution. 
4. Multiply the complex numbers (3+2i)(3-2i) 
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1. I don't know what that 3 means. Ignoring it, the log(90)=1.95424...
If it means the log(90) to some base is 3, then the base is the cube root of 90, or apx 4.4814...
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2. x+2=5
x=3
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3. 2x+3y=10
4x-6y=-28

Using determinants
2  3  -10
4 -6  28
x = -1, y = 4
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4. (3+2i)*(3-2i)
= {{{3^2 - (2i)^2}}}
= 9 - (-4)
= 13