Question 148247
Let the larger angles be A and the smaller angles be B.
You know that in any quadrilateral, the sum of the interior angles is 360 degrees, so you can write:
2A+2B = 360 Simplify this to:
A+B = 180
From the problem statement, you have that A = 3B-20, right?
Substitute this into the first equation and solve for B.
(3B-20)+B = 180
4B-20 = 180
4B = 200
B = 50 degrees.
A = 3B-20
A = 3(50)-20
A = 150-20
A = 130 degrees.