Question 148244
Find an equation of the line that goes through (1,3) and is perpendicular to the line through (0,8) and (-2,0)


Find the slope:
Difference of y's over difference of x's

{{{(8-0)/(0-2)}}} or {{{8/-2}}} or {{{-4}}}.


Find the negative reciprocal of -4.
{{{1/4}}}.  The perpendicular will have this slope.


y=mx+b is slope intercept form.


Plug in what you know:


y=1/4x+b


To find b, plug in the coordinates (1,3)


3=1/4(1)+b


Simplify

3=1/4 +b


Subtract 1/4 from 3

11/4=b.


Plug it in.

y=1/4x+11/4.  This is the equation of the line.