<PRE><B>Question 148233</B>
a chemist has two large containers of sulfuric acid solution. each has a different concentration of acid. Blending 300mls of the first solution (25% acid solution) with a currently unknown amount of the second solution (10% acid solution) gives a mixture that is 15% acid. How much of the second solution was mixed in and how much was in the final mixture?
:
Let x = amt of the 2nd solution
then
(x+300) = final amt
:
.25(300) + .10x = .15(x+300)
:
75 + .10x = .15x + 45
:
75 - 45 = .15x - .10x
:
30 = .05x
:
x = {{{30/.05}}}
x = 600 mls of the 2nd solution (10%)
:
Find the final mixture amt: (x+300), substitute 600 for x
600 + 300 = 900 mls final amt  </PRE>