Question 148196
You can always plot an equation like this to find intercepts
and slope. Each point requires an {{{x}}} and a {{{y}}}. My
way is to make {{{x = 0}}} and find {{{y}}},
then  I make {{{y = 0}}} and find {{{x}}}
{{{y = 4x + 2}}}
{{{y = 4*0 + 2}}} solve for {{{y}}}
{{{y = 2}}}
the point is ({{{0}}},{{{2}}})
then,
{{{0 = 4x + 2}}} solve for {{{x}}}
subtract {{{2}}} from both sides
{{{4x = -2}}}
{{{x = -(1/2)}}}
the point is ({{{-(1/2)}}},{{{0}}})
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Once you have any two points, you can draw the line by connecting them
When the equation is in the form
{{{y = mx + b}}}
{{{m}}} = slope
{{{b}}} = y-intercept
So, your equation {{{y = 4x + 2}}}
{{{m = 4}}} (slope)
{{{b = 2}}} (y-intercept)
I'll plot it to check:
{{{ graph( 600, 600, -10, 10, -10, 10, 4x + 2) }}}