Question 22371
Subtract "log(4x)" from each side to get 
log(2x+3)-log(4x)=2
Apply the Quotient law of logarithms to get
log[(2x+3)/4x]=2
The corresponding exponental equation is 
[(2x+3)/4x]=10^2 = 100
Multiply both sides by 4x to get the following
 2x+3=400x
    398x=3
       x= 3/398

Cheers,
Stan H.