Question 146360
Rewrite it in standard form:
x^2 + 6x + (-5) = 0

So 
a = 1 
b = 6
c = -5

Substituting the values of a, b and c into the quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

we have
{{{x = (-6 +- sqrt( 6^2-4*1*(-5) ))/(2*1) }}}
{{{x = (-6 +- sqrt( 56 ))/(2) }}}
{{{x = (-6 +- sqrt( 4*14 ))/(2) }}}
{{{x = (-6 +- 2sqrt( 14 ))/(2) }}}
{{{x = -3 +- sqrt( 14 )}}}