Question 148049
{{{(14y + 8y^2 +y^3 +12)(6 + y) }}} Start with the given expression.



{{{(6+y)(y^3+8y^2+14y+12)}}} Rearrange the terms.



{{{6(y^3+8y^2+14y+12)+y(y^3+8y^2+14y+12)}}} Expand.



{{{(6)*(y^3)+(6)*(8y^2)+(6)*(14y)+(6)*(12)+(y)*(y^3)+(y)*(8y^2)+(y)*(14y)+(y)*(12)}}} Distribute.



{{{6*y^3+48*y^2+84*y+72+y^4+8*y^3+14*y^2+12*y}}} Multiply.



{{{y^4+14*y^3+62*y^2+96*y+72}}} Now combine like terms.



 So {{{(14y + 8y^2 +y^3 +12)(6 + y)}}} expands to {{{y^4+14*y^3+62*y^2+96*y+72}}}.



In other words, {{{(14y + 8y^2 +y^3 +12)(6 + y)=y^4+14*y^3+62*y^2+96*y+72}}}.