Question 148040


Start with the given system of equations:



{{{system(3y = x+5,3x-9y = -10)}}}



{{{3y = x+5}}} Start with the first equation.



{{{y=(x+5)/(3)}}} Divide both sides by {{{3}}} to isolate {{{y}}}.



{{{y=(1/3)x+5/3}}} Simplify.



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{{{3x-9((1/3)x+5/3) = -10}}} Now plug in {{{y=(1/3)x+5/3}}} into the second equation.



{{{3x-3x-15=-10}}} Distribute.



{{{0x-15=-10}}} Combine like terms on the left side.



{{{0x=-10+15}}} Add {{{15}}} to both sides.



{{{0x=5}}} Combine like terms on the right side.



{{{0=5}}} Simplify.



Since this equation is <font size=4><b>never</b></font> true for any x value, this means that there are no solutions. So the system is inconsistent.