Question 148043
let x="gallons of 20%", so 10-x="gallons of 50%"


(20%)(x)+(50%)(10-x)=(30%)(10) Multiplying by 10 __ 2x+50-5x=30


subtracting 50 __ -3x=-20 __ dividing by -3 __ x=20/3


substituting __ 10-(20/3)=10/3