Question 148026


{{{x + 8y = 16}}} Start with the given equation.



{{{8y=16-x}}} Subtract {{{x}}} from both sides.



{{{y=(16-x)/(8)}}} Divide both sides by {{{8}}} to isolate {{{y}}}.



{{{y=-(1/8)x+2}}} Simplify.



So the equation is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/8}}} and the y-intercept is {{{b=2}}}, which is the point (0,2).