Question 22363
Yes, this is correct.

I've just confirm this problem:

{{{(5x^2-20)/(x^2+x-2)}}}
={{{5(x^2-4)/((x+2)(x-1))}}}
={{{(5*(cross(x+2))(x-2))/((cross(x+2))(x-1))}}}
={{{(5*(x-2))/(x-1)}}}