<PRE><B>Question 22349</B>
Solve the system of equations:
1) 3x + 2y = 3
2) -5x + y = 8 Multiply equation 2) by 2 then subtract equation 1) from the result and solve for x.

2) -10y + 2y = 16
1) -(3x + 2y = 3)
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3) -13x = 13 Divide both sides by -13
x = -1 Now substitute this into equation 1) and solve for y.

1) 3(-1) + 2y = 3 
-3 + 2y = 3 Add 3 to both sides.
2y = 6 Divide both sides by 2.
y = 3

Solution: (-1, 3)</PRE>