Question 147942
{{{3a^3+2}}} = {{{3(a^3)+2}}}.  So if a=1, plug a in and get {{{3(1^3)+2}}} or {{{3+2}}}.  so if a=1, then {{{3a^3+2=5}}}.  Just remember, {{{3a^3}}} is {{{3(a^3)}}} and not {{{(3a)^3}}}.  That would be {{{27a^3}}}.  So if there are no parentheses, then cube the variable first, and then multiply it by the coefficient.