Question 147925
The three angles A,B,C of a triangle ABC

{{{A+B+C=180}}}

A exceeds twice angle B by 20

{{{A=2B+20}}}

angle B

{{{B=B}}}

angle C

{{{C=180-(A+B)}}}
      or
{{{C=180-(2B+20+B)}}}

Distribute -1 

{{{C=180-2B-20-B}}}

Simplify

{{{C=160-3B}}}

Therefore,
{{{A=2B+20}}}
{{{B=B}}}
{{{C=160-3B}}}