Question 147863
Everywhere you see {{{x}}}, substitute {{{-2}}}
{{{f(x) = 5x^2 - 3x + 1}}}
{{{f(-2) = 5*(-2)^2 - 3*(-2) + 1}}}
{{{f(-2) = 20 + 6 + 1}}}
{{{f(-2) = 27}}} answer