Question 147804
{{{f(x)=4x^2-5x}}}
Wherever there is an x, replace it with the actual value,

{{{f(0)=4(0)^2-5(0)}}}
{{{f(0)=4(0)-0}}}
{{{f(0)=0}}}
.
.
.

{{{f(-1)=4(-1)^2-5(-1)}}}
{{{f(-1)=4(1)+5}}}
{{{f(-1)=9}}}
.
.
.
{{{f(2)=4(2)^2-5(2)}}}
{{{f(2)=4(4)-10}}}
{{{f(2)=16-10}}}
{{{f(2)=6}}}
Here's a graph of the function, and the 3 points.
{{{drawing( 300, 300, -4, 5, -4, 10,grid( 1 ),green(circle(0,0,.15)),green(circle(-1,9,.15)),green(circle(2,6,.15)),graph( 300, 300, -4, 5, -4, 10, 4x^2-5x) )}}}