Question 147805
{{{y=(7/5)x+2}}}
The y intercept occurs when x=0.
At x=0, then
{{{y=(7/5)x+2}}}
{{{y=(7/5)(0)+2}}}
{{{y=2}}}
Plot (0,2) on the graph
{{{drawing( 300, 300, -2, 10, -2, 10,grid( 1 ),circle( 0, 2, .2 ))}}}
Now starting at (0,2) use the slope to find another point.
Slope is rise (change in y) over run (change in x).
Starting at (0,2) with a slope of (7/5) would give you,
y:Starting y + Change in y=2+7=9
x:Starting x + Change in x=0+5=5
Plot (5,9) on the graph.
{{{drawing( 300, 300,-2,10,-2,10,grid(1),circle(0,2,.2),circle(5,9,.2))}}}
Then draw the line joining the two points.
{{{drawing( 300, 300,-2,10,-2,10,grid(1),circle(0,2,.2),circle(5,9,.2),green(line( 0, 2, 5, 9)))}}}
To complete the graph, extend the line in both directions, from the points.
{{{drawing( 300, 300,-2,10,-2,10,grid(1),circle(0,2,.2),circle(5,9,.2),green(line( -5, -5, 10, 16)))}}}