Question 147724
It's {{{sqrt((y2-y1)^2 + (x2-x1)^2)}}}
= {{{sqrt(sqrt(27)-sqrt(3))^2 + (-3 - 2)^2)}}}
={{{sqrt((12) + (-5)^2)}}}
={{{sqrt(37)}}}
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The midpoint is
((x1+x2)/2,(y1+y2)/2)
={{{(2-3)/2}}},{{{4*sqrt(3)/2)}}}
={{{-1/2}}},{{{2sqrt(3))}}}